Open Enviroments:
L_o = L_u - 4.78(\log_{10}v)^2 + 18.3(\log_{10}v) - 40.94$$ Where $v$ is the frequency in MHzL_U = 69.55 + 26.16\log_{10}v - 13.82\log_{10}h_b - C_H + (44.9 - 6.55\log_{10}h_b)\log_{10}d
Where $h_b$ is the height of the transmitter Small/Medium Cities:C_H = 0.8 + (1.1\log_{10}v -0.7)h_M - 1.56\log_{10}v
Where $h_M$ is the height of the receiver Large Cities:C_H = 3.2(log_{10}(11.75h_M))^2-4.97